Or ax 1234h or 0ffh

WebFeb 4, 2024 · (2)将存储单元 3000h 和内容送至 4000h 单元。 (3)将累加器 aX 与寄存器 cx 中的内容对调. 答案: (1)mov aX, 1234H Mov ds, ax movAx, [3000H] mov [4000H], ax xchgax, cx 12.编程:将数据段中以 Bx 为偏移地址的连续 单元的内容颠倒过来。 Web摘要 ds=091dh 孙德文微型计算机技术答案 ds=091dh 已知ds=091dh,ss=1e4ah,ax=1234h,bx=0024h,cx=5678h,bp=0024h,si 微型计算机技术第四版答案孙德文

Solved If AX-1234H and DX- 20FFH, list the sum and the

Web解答:(1)指令oR AX,1234H oR 0FFH 中的第一个oR 是指令系统中的“或”指令,而 第二个oR 是表达式中表示逻辑“或”关系的。(2)指令oR AX,1234H oR 0FFH 中的第一个 . 26 . oR … WebEngineering Computer Science 2. Choose the assembler codes to move the value 5678h from physical memory location: 1234h to accumulator (DS=100h). a) mov ax, 1234h b) mov ax, 5678hc) mov ax, (1234h) d) mov ax, [5678h]e) mov ax, [234h] D mov ax, [4678h] 2. Choose the assembler codes to move the value 5678h from physical memory location: … fischer group investment https://peaceatparadise.com

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WebExample: MOV AL, 0FFh DAS RET ; AL = 0FFh (-1) ; AL = 99h, CF = 1. CZSOPA rrrrrr. Decrement. Algorithm: operand = operand - 1 Example: ... Example: MOV AX, 1234h PUSH AX POP DX ; DX = 1234h RET 8086 instructions. Page 41 of 53. CZSOPA unchanged. Push all general purpose registers AX, CX, DX, BX, SP, BP, SI, DI in the stack. Original value of SP … WebTranscribed Image Text: Q2) if DS-3456H,SS-234AH, IP ADFCH Mov [2345H], 5675H Mov AX, 1234H ADD AX, [2345H] The final value of AX is A) 3579H b) 68A9H C) 3579D d) 1234H … Webin the al register to the bl register, given ax =1234h and 3. assembly language instructions. (Total, P, Q and R are one byte long variables and are positive numbers). Total =P-Q+R 4. Determine if the following instructions are legal or not. This problem has been solved! fischer group orange

Addressing modes in 8086 microprocessor

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Or ax 1234h or 0ffh

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WebApr 13, 2024 · 想预览更多内容,点击免费在线预览全文 Webmov ax,7FFFh add ax,2 ; SF = 1 ; Carry flag example: mov al,0FFh add al,1 ; CF = 1, AL = 00 ; Overflow flag example: mov al,+127 add al,1 ; OF = 1 mov al,-128 sub al,1 ; OF = 1 exit main ENDP END main Programming Exercises 1. Indicate whether or not each of the following instructions is valid. a. add ax,bx b. add dx,bl

Or ax 1234h or 0ffh

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Web微机系统与汇编语言复习微机系统与汇编语言简答题1. 设a186,b273q,c0bbh,它们之间的关系是 a.abc b.abcc.abc d.abc2. 80868088的存贮器组织是将存储器划分为段,可作为段的起始地址是 a.185a2 WebDec 31, 2024 · This instruction does more or less the opposite of MOV AX, [BX]: It writes data to memory. This time, the data in the register BX is written to the memory specified by the registers DS and AX. Because on x86 systems the low byte of some data is stored in the first byte and the high byte is stored in the second byte, the value 1234h would be ...

WebApr 8, 2024 · MOV [1234H], AX means that the value of AX is copied to 1234 hexadecimal address in memory. So, please correct me if what I am saying is wrong, the [] operator functions as a pointer to, right? This being said, I can't understand the following instruction: MOV [EBX], AX why the use of the [ ]? Webmov AL,0FFH mov AX,0 inc AL dec AX ∗Related instructions jc jump if carry (jump if CF = 1) jnc jump if no carry (jump if CF = 0) ∗Carry flag can be manipulated directly using stc set …

WebNov 21, 2024 · AX=FFFFh CF=1(result is not 0) SF=1 ZF=0 PF=1 OF=0 Question 2: a) Suppose that AX and BX both contains +ive numbers, and ADD AX, BX is executed , show that there is carry into the MSB but no carry out of the MSB if and only if, signed overflow occurs. Solution: As we know signed overflow occurs if and if: There is a carry into the … WebIf AX-1234H and DX- 20FFH, list the sum and the contents of each flag register bit (C, S, and Z) after the ADD AX, DX instruction executes. 2. This problem has been solved!

Weba. mov ax,12h b. mov ax,[1234h] c. mov ds:[1234h],12h d. mov al,ds:[1234h] 5. 下面源程序语句中,_____包含有寄存器寻址方式。 ... and bx,0ffh and bh,[bx] 上述指令序列运行后,bx的内容是()( b ) a. 0305h ( bcd ) a. mov al,00 b. and al,00 c. xor al,al d. sub al,al 10. 下面可以形成 ...

WebMOV AX,BҮТE1 AX=1234H AX= d. ADD DL,BYTE DX=0122H DX= e. INC DX DX=FF12H DX= f. INC DL DX=FF23H DX= g. XCHG AL,AH AX=1234H AX= h. SUB CL,CH CX=3451H CX= Question For each of the following unrelated instructions, show the result in the destination operand. Indicate if the instruction is invalid. Assume BYTE1 is defined as DB 05. fischer group wikiWebMOV AX, [BX] ; Suppose the register BX contains 4895H, then the contents ; 4895H are moved to AX ADD CX, {BX} Based addressing mode In this addressing mode, the offset … fischer group stainless restaurantsWebFeb 3, 2024 · 2. The instruction, MOV AX, 1234H is an example of - 3. The full form of FPGA is - 4. Which language could be used for programming an FPGA. 5. 8085 microprocessor has how many pins - 6. What is SIM? 7. The ROM programmed during manufacturing process itself is called - 8. The ROM programmed during manufacturing process itself is called - 9. camping sites north wales tentsWebif using BX, the operand is defaultly located in Data segment,then: PA= (DS)*10H+ (BX)+ (DI)/ (SI)+disp if using BP, the operand is defaultly located in stack segment,then: PA= (SS)*10H+ (BP)+ (DI)/ (SI)+disp 16 f Based Indexed Relative Addressing MOV [BX+DI+1234H], AH 88 ;assume (ds)=4000h, (bx)=0200h, (di)=0010h ;machine code:88A13412h A1 camping sites nelsons bayWebanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov dx, 12h mov bx, 10h div bx Choose one answer. a. DX=0006h, AX=2345h b. DX=1234h, AX=0056h c. DX=0056h, AX=1234h d. cannot be determined 19. camping sites on skyeWeb微机原理与接口技术期中考试题(带答案)_试卷_中考 camping sites northern nswWeb8. (5 points) Write a short sequence of instructions to store the contents of the CX register at theword memory location contained in CX. Thus if CX contains 1234h, the number 1234h will be stored at locations DS:1234h and DS:1235h in memory. mov bx,cx mov [bx],cx mov bx , cx mov [ bx ] , cx camping sites phillip island